fundamentos trabajo
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![Page 1: Fundamentos Trabajo](https://reader035.vdocumento.com/reader035/viewer/2022081503/563dbb66550346aa9aacd79f/html5/thumbnails/1.jpg)
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Y= A+BXA= -1.10054217mB= 1.75515mK’=2.92525mK=87.7575e-3Por lo tanto el punto de corte con el eje X para Y=0 sera aproximadamente 0.627v
![Page 3: Fundamentos Trabajo](https://reader035.vdocumento.com/reader035/viewer/2022081503/563dbb66550346aa9aacd79f/html5/thumbnails/3.jpg)
A= -4.991570932e-4B= 4.965963995e-4X=1.00693189K’=8.2766e-4K=24.8298e-3
![Page 4: Fundamentos Trabajo](https://reader035.vdocumento.com/reader035/viewer/2022081503/563dbb66550346aa9aacd79f/html5/thumbnails/4.jpg)
A=-1.830533319e-4B=1.713471581e-4X=1.068318459K’=2.855785968e-4K=8.567357904e-3
![Page 5: Fundamentos Trabajo](https://reader035.vdocumento.com/reader035/viewer/2022081503/563dbb66550346aa9aacd79f/html5/thumbnails/5.jpg)
A=3.1030587mB=5.095421506e-5X=-60.8989LAMNDA= 16.42e-3
TIPO P
M2
MOD PV30V d c
V 48V d c
0
I
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X=0.7K=
M2
MO D PV 30V d c
V 48V d c
0V 51V d c
I
M2
MOD PV 30V d c
V 48V d c
0V55V d c
I
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M2
MOD PV33V d c
V 40V d c
0
I
A=2.232655e-3
![Page 8: Fundamentos Trabajo](https://reader035.vdocumento.com/reader035/viewer/2022081503/563dbb66550346aa9aacd79f/html5/thumbnails/8.jpg)
B=9.5170255e-5X=-23.459588LAMDA=42.62549455e-3