ejercicios_tbjo_3
Post on 06-Dec-2015
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DESCRIPTION
calculo diferencial
TRANSCRIPT
EJERCICIOS ππ π(π₯) = βπ₯ + 1 π₯ 2 β 3π₯ βππππ ππ π£ππππ ππ π β² (1)
π(π₯) = (x )21+xβ2β3x
(π₯)= 12
( x ) β12
β2 xβ3βΒΏ3
πβ(1)= 12
( x ) β12
β2ΒΏ
πβ(1) = 1
2β1β2β3 = 1
2β5=1
2β10
2=β9
2
πβ(1)= -92
π(π₯) = sin β x
= sin ΒΏ
(π₯)= cosΒΏ
(π₯)= cosΒΏπ(π₯)=cos ΒΏ
( xn )'=nxnβ1 FΓ³rmula utilizada
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