problemas del profesor

8/17/2019 Problemas Del Profesor

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PROBLEMA NO ESTÁ DESCRITO.

BALANCES DE MATERIA

Gas de entrada 15 pie3 /s Gas de salida

GNp+1 = 003!"# l$ %&l / s 're()p = *1 ,1 /,Np+1- . 100

GNp+1 = 13#"0 l$ %&l / 2 ,1 = * 1 0#0 -.,Np+1

Np+1 = 00000 ,1 = 0003!3

,Np+1 = 003!30 1 = 0003

Gs = 131# l$ %&l / 2 G1 = 130!"1! l$ %&l / 2

L4)id& de entrada L4)id& de salida

60 = 000050

70 = 000050 6N8 = 6& + * ,Np+1 ,1 - / * Ls/Gs -

* Ls/Gs- %4n = * ,Np+1 ,1 - / * 6Np%a7 6& - 6Np = 00"0

6Np%a7 = 005!5 7Np = 001!

LNp = 1"0!150 l$ %&l / 2

*Ls/Gs-%4ni%& 9 0##"1

*Ls/Gs-real =15 *Ls/Gs-%4ni%& = 133#

Ls = 131#35! l$ %&l / 2

L0 = 13"51! l$ %&l / 2

N:MER; DE 8LAT;S IDEALES

l&<

Np+1 % 7& . * 1 1/A -

+ * 1/A - Np = 1 % 7&

l&< A

% = 10#00

GNp+1 = 13#"05 l$ %&l / 2 Np+1 = 00 A&nd&s = LNp /%.GNp+1 = 11355

LNp = 1"0!1500 l$ %&l / 2 7Np = 001! At&pe= L0 /%.G1 = 11305

G1 = 130!"1! l$ %&l / 2 1 = 0003

L0 = 13"51!0 l$ %&l / 2 70 = 00

Apr&% = 11!1!! Npideales = 5# .


36/40

,%+1 = ,1 + *Ls / Gs- *6% 6&- = ,N8+1 *Ls / Gs- *6Np 6%-6 = , / *10# + 00# ,-

, 6

1 0003!3 0005!53

001303# 0011##

3 0001# 001!!!

00# 00"5 003#03" 0035##

00501# 005!1! ∆%a&r = 3E05

"00"31

∆%en&r =!5"E0"

Npideales = 5##

N:MER; DE 8LAT;S REALES

ρL = 15 l$/pie3

ρL

= 313#µL = 10 (p

%

ML µL

% = 10#

ML =1"##"# l$/l$ %&l

Ε

&(

=

050 Npreales = 11#!!

DIAMETR; T;RRE 8LAT;S > = 0"0 >? >? = C? *ρLρG-/ρG-1/ *σ /0-0

GNp+1 = 13#"05 l$ %&l / 2 Np+1 = 000000

LNp = 1"0!150 l$ %&l / 2 7Np = 00

G1 = 130!"1! l$ %&l / 2 1 = 0003

L0 = 13"51! l$ %&l / 2 7& = 0000500

L@ = L1 M pr&% = 30"051"! l$ / 2 ρL = 150000 l$/pie3

M pr&% = 1"#"5!! l$/l$ %&l

G@ = G1 M pr&% = 3##" l$ / 2 ρG = 00"305 l$/pie3

M pr&% = !530 l$/l$ %&l

*L@/G@- . *ρG /ρL-05 = 00!5

As)%iend& )n espa(ia%ient& t = 0 p)l = !53305! pies/sAn = F / > ρG F = 10#5! l$/sAn = 1"5"## pie

AST = An / * 1β - α = 0 026825 β = 01000

AST = 1 9532767 pie

D = 15""0 pies

Alt)ra de la t&rre = *Np 1-. t = 00 p)l


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DIAMETR; T;RRE RELLENA

G1 = 13#"05 l$ %&l / 2 1 = 000000

L1 = 1"0!150 l$ %&l / 2 71 = 00

G = 130!"1! l$ %&l / 2 = 0005#1

L = 3"#0035 l$ %&l / 2 7 = 0000000

L@ = L1 M pr&% = 30"051"! l$ / 2 ρL = 150000 l$/pie3

M pr&% = 1"#"5!! l$/l$ %&l

G@ = G1 M pr&% = 3##" l$ / 2 ρG = 00"305 l$/pie3

M pr&% = !530 l$/l$ %&l

*L@/G@- . *ρG /ρLρG-05 = 00!1

Del dia


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β

= G . C *µL-01 . J 010!00 ∆8/ = 00 *N/%-/%

ρG . *ρL ρG- .


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?;ND;S G1 = 101"5 %&l / 2% 1 = 001500

71 = 0005!

L1 = 3""0#1" %&l / 2% 1. = 000##

M pr&% = 1!"5"

L1 = 1#"#3 < / 2% *1 -.M1 = 0#!"5!

KGa = 311"! %&l / 2%3at%

Ka = 311"! %&l / 2%3 t;G 1 = 0110 %

t;G = 00! %

:NIDADES GL;BALES DE TRANS?ERENCIA DE MASA 5 p)nt&s

Nt;G =1 * .-M = 0001#

* .-M

Nt;G = !!531 ALT:RA DE RELLEN; = 5!5# %

ln

1 % 7 . * 1 1/A - + * 1/A -

Nt;G = % 7

1 1/A

% = 1"500

G1 = 101"51" l$ %&l / 2 1 = 0015000 A&nd&s = L1 /%.G1 = 1"!!33

L1 = 3""0#1" l$ %&l / 2 71 = 0005!0

G = 13!115# l$ %&l / 2 = 000030 At&pe= L /%.G = 1#3"1

L = 30"103 l$ %&l / 2 7 = 0000000

Apr&% = 1!55!"

Nt;G = !"! ALT:RA DE RELLEN; = 5505 %

DIAMETR; T;RRE RELLENA 3 p)nt&s

Re()pera(iHn de a(et&na = 300


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,%+1 = ,1 + *Ls / Gs- *6% 61- = ,Np+1 *Ls / Gs- *6% 6Np-6 = , / *1"5 + 0"5 ,-

, 6

1 0000305 00001"

0000"5# 00003

3 00013! 0000!1

000# 00013#! Npideales = "1#3

5 0003#5" 0005" 0000 000353

" 000#53! 0005!! 001!5 000! ∆%a&r = 10"E05

001"#5 ∆%en&r = !5!E0

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