previo_6.2
TRANSCRIPT
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U.N.M.S.MFacultad de Ing. Electrnica, Elctrica y
Telecomunicaciones
Apellidos y Nombres Matricula
Arroyo Angeles, Alredo !scar "#"$%"%%
&urso Tema
'ispositi(osElectrnicos
E) T*ANSIST!* +I!)A* N&A*A&TE*-STI&AS +SI&AS
Inorme Fec/as Nota
re(io *eali0acin Entrega
N1mero
""2%32"3 ""2%32"33
4rupo roesor
"%56iernes 728pm9 Ing. )uis aretto :.
EL TRANSISTOR BIPOLAR PNP
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CARACTERSTICAS BSICAS
OBJETIVOS:
6eriicar las condiciones de un transistor bipolar N. &omprobar las caracter;sticas de uncionamiento de un transistor bipolar N
CUESTIONARIO PREVIO
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ara *"@ #3C
'onde?
Vth=R
2xVcc
R1+R2=
22kx12V
56k+22k=3.385V
Rb
=R
2x R
1
R1+R2=
22k x56 k
56k+22k=15.795 k
'el graico (emos?
Ie = Re D 6eb D Ib = Rb @ 6t/ 5a9
ero
Ie @ Ib 5D"9
*eempla0ando en la ecuacin 5a9?
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Ib 5D"9= Re D 6eb D Ib = Rb @ 6t/5b9
Ib= VthVeb(+1 )x Re+Rb 5c9GVeb=Vbe
ero @ $%
*eempla0ando en la ecuacin 5c9?
Ib= 3.38V0.6V
(90+1 )x 330+15.79 k
Ib @ 60.890HA
Ademas? ICQ @ = Ib
ICQ @ $%=60.890 HA @ #.481mA
'el graico (emos?
Ie = Re D 6ec D Ic = Rc @2 6cc
6ce @ Ic = Re D Ic = Rc D 6cc @ 5.481mA5
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6ce @ 28."%6
Ve=IeRe
Ve=5 .540mA330
Ve=1.828V
Tabla 2
*"@#3C Ic5mA9 Ib5HA9 6ce5(9 6be5(9 6e5(9
Terico #.8J" 3%.J$% $% 28."% %.3 ".J7J
ara *@3JC
'onde ?
Vth=R
2xVcc
R1+R2=22k x12V
68
k+22
k
=2.933V
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Rb=R
2x R
1
R1+R2=
22k x 68k
68k+22k=16.622k
'el graico (emos?
Ie = Re D 6eb D Ib = Rb @ 6t/ 5a9
ero
Ie @ Ib 5D"9
*eempla0ando en la ecuacin 5a9?
Ib 5D"9= Re D 6eb D Ib = Rb @ 6t/5b9
Ib= VthVeb
(+1 )x Re+Rb 5c9GVeb=Vbe
ero @ $%
*eempla0ando en la ecuacin 5c9?
Ib=
2.933V0.6V
(90+1 )x 330+16.622 k
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Ib @50.008HA
Ademas? ICQ @ = Ib
ICQ=90x 50.008A=4.500mA
'el graico (emos?
Ie = Re D 6ec D Ic = Rc @2 6cc
6ce@Ic = Re D Ic = Rc D 6cc @ 3.J7mA5
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*"@3JC Ic5mA9 Ib5HA9 6ce5(9 6be5(9 6e5(9
Terico 8.#%% #%.%%J $% 27.J3%7 %.3 7.7%7
6ariando " a "%%C
'onde ?
R
( 1+P1)+R2=
22k x12V
(56 k+100k)+22k=1.483V
Vth=R2xVcc
R
R
( 1+P1)+R2=
22 kx (56 k+100k)(56 k+100 k)+22k
=19.2809 k
R2x
( 1+P1)
Rb=
'el graico (emos?
Ie = Re D 6eb D Ib = Rb @ 6t/5a9
ero
Ie @ Ib 5D"9
*eempla0ando en la ecuacin 5a9?
Ib 5D"9= Re D 6eb D Ib = Rb @ 6t/5b9
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Ib @VthVeb
(+1 )x Re+Rb 5c9GVeb=Vbe
ero @ $%
*eempla0ando en la ecuacin 5c9?
Ib= 1.483V0.6V
(90+1)x 330+19.280 k
Ib=17.907A
Ademas? ICQ @ = Ib
ICQ=90x 17.907A=1.611mA
'el graico (emos?
Ie = Re D 6ec D Ic = Rc @2 6cc
6ce @ Ic = Re D Ic = Rc D 6cc @ ".3""mA5
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6ariando " a 7#%C
'onde ?
R
( 1+P1)+R2=
22k x12V
(56 k+250k)+22k=0.8049V
Vth=R2xVcc
R
R
( 1+P1)+R2=
22 kx (56 k+250 k)(56 k+250 k)+22k
=20.524 k
R2x( 1+P1)
Rb=
'el graico (emos?
Ie = Re D 6eb D Ib = Rb @ 6t/ 5a9
ero
Ie @ Ib 5D"9
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*eempla0ando en la ecuacin 5a9?
Ib 5D"9= Re D 6eb D Ib = Rb @ 6t/5b9
Ib @VthVeb
(+1 )x Re+Rb 5c9GVeb=Vbe
ero @ $%
*eempla0ando en la ecuacin 5c9?
Ib= 0.8049V0.6V
(90+1)x 330+20.524 k
Ib=4.053 A
Ademas? ICQ @ = Ib
ICQ=90x 4.053A=0.364mA
'el graico (emos?
Ie = Re D 6ec D Ic = Rc @2 6cc
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6ce @ Ic = Re D Ic = Rc D 6cc @ %.
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Ie @ Ib 5D"9
*eempla0ando en la ecuacin 5a9?
Ib 5D"9= Re D 6eb D Ib = Rb @ 6t/5b9
Ib @VthVeb
(+1 )x Re+Rb 5c9GVeb=Vbe
ero @ $%
*eempla0ando en la ecuacin 5c9?
Ib=
0.457V0.V
(90+1
)x 330+21.163 k
Ib=8.927 A
Ademas? ICQ @ = Ib
ICQ=90x 8.927A=0.803mA
'el graico (emos?
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Ie = Re D 6ec D Ic = Rc @2 6cc
6ce @ Ic = Re D Ic = Rc D 6cc @ %.J%
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Ie @ Ib 5D"9
*eempla0ando en la ecuacin 5a9?
Ib 5D"9= Re D 6eb D Ib = Rb @ 6t/5b9
Ib @VthVeb
(+1 )x Re+Rb 5c9GVeb=Vbe
ero @ $%
*eempla0ando en la ecuacin 5c9?
Ib=
0.245V0V
(90+1
)x 330+21.551 k
Ib=4.749 A
Ademas? ICQ @ = Ib
ICQ=90x 4.749 A=0.427mA
'el graico (emos?
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Ie = Re D 6ec D Ic = Rc @2 6cc
6ce @ Ic = Re D Ic = Rc D 6cc @ %.87mA5