marco teórico turbinas pelton
TRANSCRIPT
-
8/17/2019 Marco Teórico Turbinas pelton
1/12
. 6:
E ( M; ε T =
/ =0). L ,
. S
.
1.1
T ( F 1)
1.1.1
: L ,
. L .
1.1.2
: 0 ( ). L . L
.
1.1.3 : . R . A
.
F 1.1 E ; , 0, 0
-
8/17/2019 Marco Teórico Turbinas pelton
2/12
+
+ −
F. 1.2 T P . C C
L P :
1.
2. . E P. T
( ≥ 150/)
3.
4. . D . B
( , 4000 ,
; )
5. . P , .
6. .
-
8/17/2019 Marco Teórico Turbinas pelton
3/12
7.
8.
9. .
10. .
11. .
12.
,
13. . P
.
14. . E
F. 1.
E
22/2
. E
. U 25
,
.
T P C
, α1=0; β1=180
. E
. I, 2=0;
. P
, 2
2=1=; β2=0.
-
8/17/2019 Marco Teórico Turbinas pelton
4/12
E P :
1 = 2 =
.
S :
1 = 2
1 < 2 .
=0,97; H =
: ⁄
,
. ,.√ ; 2; 3/
F 1.4 I T P
S F1.4, α 25 β 35 40.
E .
D
.
3.1 ( 1.5)
P :
/ 2,83,2 / 2,42,8 / 1,101,20 / 0,80,
β
α
-
8/17/2019 Marco Teórico Turbinas pelton
5/12
F 1.5 P
3.2
E ,
F 1.6 A
S , .
D , ( 2=(2)
1/2),
Q/2
-
8/17/2019 Marco Teórico Turbinas pelton
6/12
F 1.7 F
( ):
( − )
S α , 1 = 2 = ; , :
(1 + )/2
:
= (1 + )
.
= = (1 + ); R:
.
= . ;
E , ,
=.
= ( − )(1 + )
E , :
= . = ( − )(1 + )
-
8/17/2019 Marco Teórico Turbinas pelton
7/12
L ,
. S P/=0,
=/2; N = /(2πD)
F,
= 1/4(1 + )
U ρQ ,
P = ρQ 2. E :
= 2( − )(1 + )
= /2
= 1 2⁄ (1 + )
= ⁄ ⁄ → = 286
2,4 < < 30; 1
100 <
< 1
10
-
8/17/2019 Marco Teórico Turbinas pelton
8/12
F 1.8 C P D=360, 1
-
8/17/2019 Marco Teórico Turbinas pelton
9/12
E G
P.
L
160. L
,
.
E ,
, .
F 1.9 V T. T A P F :
• R P
o M
o P
o E T P
o S P ,
.
• R F
o L . R
-
8/17/2019 Marco Teórico Turbinas pelton
10/12
T
PF 1.
S
E
(
P
:
0 C TP
.
, ,
)
,
= . ( + ).
− . S R
-
8/17/2019 Marco Teórico Turbinas pelton
11/12
E
T 1. C T P
= ( + ). = = (1 + )
S = , R.
S = − , , : =
S 1 = 2 M
, :
T 2. C T P
= ( − )( + ) = . = ( − )(1 + )
L = /2,
N = /4πR, :
T 3. C T P
= 1/4
( + ) = 1/4
(1 + )
E , P = ρQ2, :
T 4. C T P
= 1/2( + ) = 2( − )(1 + )
S 87% 90% .
.
, , .
2
-
8/17/2019 Marco Teórico Turbinas pelton
12/12
3 10000
30 300.
2.
F 1.11 D
T 6. D U M T
K Q