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2 tn/m
k =3tn k =4 tn
4 tn3 tn
2m 3m 2m 6m 4m
A B C D E
0.4
0.6
HALLAR LA SIGUIENTE VIGA POR SLOPE DEFLECTION :θB,θC ,θD,C y , y D y ,
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2 tn/m
k =3tn k =4 tn
4 tn
By Cy Dy
A B C D
3tn
Bx
Ey
1. Propiedades
I=0.4(0.6)3
12=0.0072m4
A=0.4 (0.6 )=0.24m2
E=2Tn /m2
α=4 ° c−1
2. Fuerzas debido al Empotramiento perfecto
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6
3
1.92
1.408 2.592
2.88
6
6
6 6
4 tn
2 tn/m
3. Fuerzas debido al Cambio de Temperatura
Faxial=E . A .α .(T ¿+T inf2 )
Momento=E . A .α .(T¿−T inf2 )
Faxial=2 (0.24 ) (4 )( 30+202 )=48 tn
Momento=2¿
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0.96
48 48
0.960.96
48
0.96
48
5.76
19.2
5.765.76
19.2
5.76
19.219.2
Faxial=2 (0.24 ) (4 )( 40+(−20)2 )=192 tn
Momento=2¿
Entonces:
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0.96
48 48
0.960.96
48
0.96
48
5.76
19.2
5.765.76
19.2
5.76
19.219.2