diseño escalera
DESCRIPTION
escaleraTRANSCRIPT
0.17
Muro portante
de albañileria 0.17
0.70 m
metros : 0.25 b = 1.60 2.10 0.40
Ln = 3.70 m
DATOS :
f'c = 280 Kg/cm²
fy = 4200 Kg/cm²
P = 30 cm
Cp = 18 cm
s/c = 600 Kg/m²
PREDIMENSIONAMIENTO :
Espesor : t = 0.15 m Asumimos :
t = 0.17 cm
t = 0.19 m
Cos Ø = 0.857
Altura eq. : hm = 28.84 cm
METRADO DE CARGAS :
CM : P.P = hm * b * 2.4 * 1.4 = 1.55 Tn/m
Acabado = 0.10 * b * 1.4 = 0.224 Tn/m
CV : S/C = s/c * b * 1.7 = 1.632 Tn/m
Wu2 = 3.41 Tn/m
CM : P.P = t * b * 2.4 * 1.4 0.914 Tn/m
Wu1 = 2.77 Tn/m
DISEÑO ESCALERA
Cos (Ɵ) = 𝑃
𝑃2+𝐶𝑝2
hm = 𝑡
𝐶𝑜𝑠 𝚹 +
𝐶𝑝
2
t = 𝐿𝑛
25
t = 𝐿𝑛
20
3.41 Tn/m
2.77 Tn/m
RA RB
1.73 m 2.30 m
Lt = 4.025 m
RB = 6.62 Tn
Xo = 1.943 m
= 6.433 Tn-m
; α = 0.8 = 5.146 Tn-m
ELECCION DEL REFUERZO :
Ø = 1/2 pulg.
Asb= 1.27 cm²
Recub. = 2.00 cm
Peralte efectivo : d= 14.37 cm
Asumimos que : a = 2 cm
As = 10.78 cm a = 1.12 cm
Por lo tanto se usara: N° varillas = 8
Acero = Ø 1/2 @ 25.00
RB =[ 𝑊𝑢1 ∗ 𝐿𝑡2
2 + (Wu2 - Wu1)* L2 * (L1 + 𝐿2
2 )] / Lt
Vx = 𝑅𝐵 − 𝑊𝑢2 ∗ 𝑋𝑜 = 0
(+) Mu max = 𝑅𝐵 ∗ 𝑋𝑜 − 𝑊𝑢2 ∗𝑋𝑜2
2
(-) Mu dis = α ∗ 𝑀𝑢 max
As=𝑀𝑢
Ø 𝑓𝑦 (𝑑−𝑎
2) a =
𝐴𝑠 𝑓𝑦
0.85 𝑓′𝑐 𝑡
d = t − (𝑅𝑒𝑐𝑢𝑏. +Ø𝑣𝑎𝑟
2)
a = 𝑑
5