DESARROLLO DEL EXAMEN FINAL DE TEORIA DEL BUQUE

PROBLEMA 7:B = 10mD = 10mT = 6,5m H = 6,25m

Para la Lnea de Flotacin 2F

2F

HBH*B

5,830,000,00

6,356,6142,00

6,888,6659,58

7,409,6871,65

7,9210,0079,20

8,449,6881,72

8,968,6677,60

9,486,6162,70

10,000,000,00

S = SPACING OF STATIONSTRIMMED DISPLACEMENTS AND CENTERSSHEET

SHIP

S = 1,25mDATE

S/3 = 0,417mBY

STATIONSM VOLSM MT.SECTION AREAS TO TRIM LINES

SUBDIVIS. LOAD LINE3A2A1APAR1F2F3F

01,00-4,000,000,000,000,000,000,000,00

14,00-12,0060,9862,7064,4266,1454,1142,0029,96

22,00-4,0073,0977,6082,1086,6073,0959,5845,99

34,00-4,0074,1781,7289,2796,8384,2471,6558,97

42,000,0068,8079,2089,60100,0089,6079,2068,80

54,004,0058,9771,6584,2496,8389,2781,7274,17

62,004,0045,9959,5873,0986,6082,1077,6073,09

74,0012,0029,9642,0054,1166,1464,4262,7060,98

81,004,000,000,000,000,000,000,000,00

SM VOL * A = f(V)1272,091465,071657,751850,161657,751465,071272,09

SM MT. * A = f(M)-541,49-360,77-179,990,00179,99360,77541,49

() DISPLACEMENT = f(V)*S/3 510,509530,037610,444690,728770,902690,728610,444530,037

() DW. VOLUME = () - V19,52899,935180,219260,393180,21999,93519,528

() LCB = [ f(M)/f(V) ]*S 0,000-0,532-0,308-0,1360,0000,1360,3080,532

() SHIFT OF LCB = () - x -0,532-0,308-0,1360,0000,1360,3080,532

() CG. DW. FROM LCB = [LOAD DISPLACEMENT / DW. VOLUME] * ()-13,910-1,572-0,3840,0000,3841,57213,910

() CG. DW. FROM S. MEDIA () + ()-14,442-1,880-0,5200,0000,5201,88014,442

Por lo tanto para la flotacin 2F:RPTA (c) RPTA (d)

JULIO ALCENI CONTRERAS GOMEZ20074095J