7/24/2019 4 punto

1/3

Programa serie de Fourier en MATLAB:

close all

clc

syms tn

A = [-2 -1 0 1 2]

! = [0 -2 1 0 ]

! = sym"!#

T = ma$ "A#-min"A#

%o = 2&'i("T#

Ao = 0

!ori=1:lengt)"!#

Ao = Ao * int"!"i#+,t,+ A"i# + A"i*1##

end

Ao = sim'le "Ao(T#

An = 0

!ori=1:lengt)"!#

An = An *int"!"i#&cos"n&%o&t#+A"i#+A"i*1##

end

An = sim'le"2&An(T#

Bn = 0

!ori=1:lengt)"!#

Bn = Bn *int"!"i#&sin"n&%o&t#+A"i#+A"i*1##

end

Bn = sim'le"2&Bn(T#

An = c)ar"An#

Bn = c)ar"Bn#

An = sim'le"sym"strre'"c)ar"An#+ ,sin"'i&n#,+,0,###

Bn = sim'le"sym"strre'"c)ar"Bn#+ ,sin"'i&n#,+,0,###

An = sim'le"sym"strre'"c)ar"An#+ ,cos"'i&n#,+,"1#.n,###

Bn = sim'le"sym"strre'"c)ar"Bn#+ ,cos"'i&n#,+,"-1#.n,###

An = sim'le"sym"strre'"c)ar"An#+ ,sin"2&'i&n#,+,0,###

Bn = sim'le"sym"strre'"c)ar"Bn#+ ,sin"2&'i&n#,+,0,###

An = sim'le"sym"strre'"c)ar"An#+ ,cos"2&'i&n#,+,1,###

Bn = sim'le"sym"strre'"c)ar"Bn#+ ,cos"2&'i&n#,+,1,###

/

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dis'",Ao,#

'retty"Ao#

dis'",An,#

'retty"An#

dis'",Bn,#

'retty"Bn#

$ = lins'ace "min"A#+ma$"A#+ 1000#

!$ = 0

!ori=1:lengt)"A#-1

i!mod"i+2# == 1

!$ = !$*""$A"i##"$=A"i*1###3&su4s"!"i#+$#

else

!$ = !$*""$A"i##"$A"5*1###3&su4s"!"i#+$#

end

end

'lot"$+!$+,Line%idt),+2# )old on

'lot"$*ma$"$#-min"$#+!$+ ,line%idt),+ 2#

'lot"$-ma$"$# *min"$#+!$+ ,line%idt),+ 2#

'lot"[ma$"$# ma$"$#]+[!$"1# !$"end#]+,line%idt),+2#'lot"[min"$# min"$#]+[!$"end# !$"1#]+,line%idt),+2#

grid on

$la4el",(4!T56MP7,#

yla4el",(4!AMPL5T89,#

title",(4!;AF5

7/24/2019 4 punto

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En este caso nuestro periodo es de 2 , entonces:

La serie de fourier queda :

o