2. prova de sma301-calculo i - professor alexandre 29.04...

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2 . PROVA DE SMA301-C ´ ALCULO I - Professor Alexandre 29.04.2013 - A NOME: N o . USP: NOTA: Quest˜ ao Resposta Valor Quest˜ ao Resposta Valor 01 a . (a) (b) (c) (d) (e) 06 a . (a) (b) (c) (d) (e) 02 a . (a) (b) (c) (d) (e) 07 a . (a) (b) (c) (d) (e) 03 a . (a) (b) (c) (d) (e) 08 a . (a) (b) (c) (d) (e) 04 a . (a) (b) (c) (d) (e) 09 a . (a) (b) (c) (d) (e) 05 a . (a) (b) (c) (d) (e) 10 a . (a) (b) (c) (d) (e) Regras: 1- ´ UNICA SEM RASURA 2- 3- 01 . Quest˜ ao: x!0 x 4 + 5x - 1 2 - p x 2 + 4 x!1 x 3 - 1 (x - 1) 2 +1 -1 +1 02 . Quest˜ ao: f(x)= |x + 1| - p x 2 + 2 f [0, 1] y = 1 y = -1 f x = 1 2 y = 2 f [0, 1] x = 1 x = -1 f [0, 1] f y = 1 y = -1 03 . Quest˜ ao: f(x)= x + 1, x , |x| + 1, x . g(x)= f(x) |x| . f R f (-1,0] g f x = 0 g (0, 1) g f [0, 1) g x = 0 g f g R g 04 . Quest˜ ao: f :[a, b] ! R f f f M m (f)=[m, M] c, d 2 [a, b] 2 (min{f(c),f(d)}, max{f(c),f(d)}) p 2 (c, d) f(p)= f p 2 [a, b] f(p)= 0 (ii) (iii) (i) (ii) (iii) (iv) (i) (ii) (iv)

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Page 1: 2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04 ...conteudo.icmc.usp.br/pessoas/andcarva/sma301/Prova02_A_B_C_D.pdf · 2. PROVA DE SMA301-CALCULO I - Professor Alexandre

2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04.2013 - A

NOME: No. USP: NOTA:

Questao Resposta Valor Questao Resposta Valor

01a. (a) (b) (c) (d) (e) 06a. (a) (b) (c) (d) (e)

02a. (a) (b) (c) (d) (e) 07a. (a) (b) (c) (d) (e)

03a. (a) (b) (c) (d) (e) 08a. (a) (b) (c) (d) (e)

04a. (a) (b) (c) (d) (e) 09a. (a) (b) (c) (d) (e)

05a. (a) (b) (c) (d) (e) 10a. (a) (b) (c) (d) (e)

Regras: 1 - UNICA SEM RASURA2 -3 -

01. Questao:x!0

x

4 + 5x- 1

2-px

2 + 4

x!1

x

3 - 1

(x- 1)2

+1-1

+1

02. Questao: f(x) = |x+ 1|-px

2 + 2

f [0, 1] y = 1 y = -1

f x = 1

2

y = 2

f [0, 1] x = 1 x = -1

f [0, 1]

f y = 1 y = -1

03. Questao:

f(x) =

�x+ 1, x ,

|x|+ 1, x .

g(x) =f(x)

|x|.

f Rf (-1, 0] g

f x = 0 g (0,1) g

f [0,1) g x = 0 g

f g R g

04. Questao: f : [a, b] ! R

f f

f M m (f) = [m,M]

c, d 2 [a, b] ⇠ 2 (min{f(c), f(d)},max{f(c), f(d)}) p 2 (c, d) f(p) = ⇠

f p 2 [a, b] f(p) = 0

(ii) (iii)

(i) (ii) (iii) (iv)

(i) (ii) (iv)

Page 2: 2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04 ...conteudo.icmc.usp.br/pessoas/andcarva/sma301/Prova02_A_B_C_D.pdf · 2. PROVA DE SMA301-CALCULO I - Professor Alexandre

05. Questao: f : R ! R f(x) =

�a+ bx, x > 2

3, x = 2

b- ax

2

, x < 2

a, b 2 R

f a- b = 2

b- a = 2 f

a 2 (-1

2

, 0] b 2 [1, 2) f

f

a 2 (-1

2

, 0] b 2 [0, 1) f

06. Questao: f : R \ {0} ! R f(x) = x

1

|x|

x!-1f(x) =

u!0

-

u

u

f

f(0)

f

f

07. Questao:x!1

1

x

= 1

" > 0 � =

�1

2

,

"

2

�0 < |x- 1| < �

����1

x

- 1

���� < "

" > 0 � = {1, 2"} 0 < |x- 1| < �

����1

x

- 1

���� < "

" > 0 � =

�1

2

,

"

2

� ����1

x

- 1

���� < " 0 < |x- 1| < �

" > 0 � = {1, 2"}

����1

x

- 1

���� < " 0 < |x- 1| < �

x!1

1

x

= 1

x!1

+

1

x

= 1

x!1

-

1

x

= -1

08. Questao:x!0

⇣x

2 (3x)1- (x)

�x

2

�.

1

12

7

6

09. Questao: p(x) = 32x

5 - 80x

4 - 80x

3 + 200x

2 + 18x- 45

p(x)

p(x)

p(x)

p(x)

p(x)

10. Questao: f(x) =

✓2+ (

x

3 - 2

x

2 + 1

)

◆1+ (x2)

f

0(x) =�1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) =⇣2+

⇣x

3-2

x

2+1

⌘⌘1+ (x2)

1+ (x2)

2+⇣

x

3-2

x

2+1

⌘⇣

x

3-2

x

2+1

⌘x

4+3x

2+4x

(x2+1)2 - 2x (x2)⇣2+

⇣x

3-2

x

2+1

⌘⌘�

f

0(x) =h ⇣

x

2-2

x

2+1

⌘ �1+ (x2)

�+ [1+ (x2)]

⇣2+

⇣x

3-2

x

2+1

⌘⌘i⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) = 6x

(x2+1)2

⇣x

2-2

x

2+1

⌘ �1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) = -2x (x2)�1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

Page 3: 2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04 ...conteudo.icmc.usp.br/pessoas/andcarva/sma301/Prova02_A_B_C_D.pdf · 2. PROVA DE SMA301-CALCULO I - Professor Alexandre

2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04.2013 - B

NOME: No. USP: NOTA:

Questao Resposta Valor Questao Resposta Valor

01a. (a) (b) (c) (d) (e) 06a. (a) (b) (c) (d) (e)

02a. (a) (b) (c) (d) (e) 07a. (a) (b) (c) (d) (e)

03a. (a) (b) (c) (d) (e) 08a. (a) (b) (c) (d) (e)

04a. (a) (b) (c) (d) (e) 09a. (a) (b) (c) (d) (e)

05a. (a) (b) (c) (d) (e) 10a. (a) (b) (c) (d) (e)

Regras: 1 - UNICA SEM RASURA2 -3 -

01. Questao:x!0

x

4 + 5x- 1

2-px

2 + 4

x!1

x

3 - 1

(x- 1)2

+1+1

-1

02. Questao: f(x) = |x+ 1|-px

2 + 2

f x = 1

2

y = 2

f [0, 1] y = 1 y = -1

f [0, 1] x = 1 x = -1

f y = 1 y = -1

f [0, 1]

03. Questao:

f(x) =

�x+ 1, x ,

|x|+ 1, x .

g(x) =f(x)

|x|.

f g R g

f [0,1) g x = 0 g

f x = 0 g (0,1) g

f (-1, 0] g

f R

04. Questao: f : [a, b] ! R

f f

f M m (f) = [m,M]

c, d 2 [a, b] ⇠ 2 (min{f(c), f(d)},max{f(c), f(d)}) p 2 (c, d) f(p) = ⇠

f p 2 [a, b] f(p) = 0

(i) (ii) (iii) (iv)

(ii) (iii)

(i) (ii) (iv)

Page 4: 2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04 ...conteudo.icmc.usp.br/pessoas/andcarva/sma301/Prova02_A_B_C_D.pdf · 2. PROVA DE SMA301-CALCULO I - Professor Alexandre

05. Questao: f : R ! R f(x) =

�a+ bx, x > 2

3, x = 2

b- ax

2

, x < 2

a, b 2 R

f a- b = 2

b- a = 2 f

a 2 (-1

2

, 0] b 2 [0, 1) f

f

a 2 (-1

2

, 0] b 2 [1, 2) f

06. Questao: f : R \ {0} ! R f(x) = x

1

|x|f

f

f(0)

f

x!-1f(x) =

u!0

-

u

u

07. Questao:x!1

1

x

= 1

" > 0 � =

�1

2

,

"

2

� ����1

x

- 1

���� < " 0 < |x- 1| < �

" > 0 � = {1, 2"} 0 < |x- 1| < �

����1

x

- 1

���� < "

" > 0 � =

�1

2

,

"

2

�0 < |x- 1| < �

����1

x

- 1

���� < "

" > 0 � = {1, 2"}

����1

x

- 1

���� < " 0 < |x- 1| < �

x!1

1

x

= 1

x!1

+

1

x

= 1

x!1

-

1

x

= -1

08. Questao:x!0

⇣x

2 (3x)1- (x)

�x

2

�.

1

7

6

12

09. Questao: p(x) = 32x

5 - 80x

4 - 80x

3 + 200x

2 + 18x- 45

p(x)

p(x)

p(x)

p(x)

p(x)

10. Questao: f(x) =

✓2+ (

x

3 - 2

x

2 + 1

)

◆1+ (x2)

f

0(x) =�1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) =h ⇣

x

2-2

x

2+1

⌘ �1+ (x2)

�+ [1+ (x2)]

⇣2+

⇣x

3-2

x

2+1

⌘⌘i⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) =⇣2+

⇣x

3-2

x

2+1

⌘⌘1+ (x2)

1+ (x2)

2+⇣

x

3-2

x

2+1

⌘⇣

x

3-2

x

2+1

⌘x

4+3x

2+4x

(x2+1)2 - 2x (x2)⇣2+

⇣x

3-2

x

2+1

⌘⌘�

f

0(x) = 6x

(x2+1)2

⇣x

2-2

x

2+1

⌘ �1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) = -2x (x2)�1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

Page 5: 2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04 ...conteudo.icmc.usp.br/pessoas/andcarva/sma301/Prova02_A_B_C_D.pdf · 2. PROVA DE SMA301-CALCULO I - Professor Alexandre

2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04.2013 - C

NOME: No. USP: NOTA:

Questao Resposta Valor Questao Resposta Valor

01a. (a) (b) (c) (d) (e) 06a. (a) (b) (c) (d) (e)

02a. (a) (b) (c) (d) (e) 07a. (a) (b) (c) (d) (e)

03a. (a) (b) (c) (d) (e) 08a. (a) (b) (c) (d) (e)

04a. (a) (b) (c) (d) (e) 09a. (a) (b) (c) (d) (e)

05a. (a) (b) (c) (d) (e) 10a. (a) (b) (c) (d) (e)

Regras: 1 - UNICA SEM RASURA2 -3 -

01. Questao:

f(x) =

�x+ 1, x ,

|x|+ 1, x .

g(x) =f(x)

|x|.

f g R g

f [0,1) g x = 0 g

f x = 0 g (0,1) g

f (-1, 0] g

f R

02. Questao: f : [a, b] ! R

f f

f M m (f) = [m,M]

c, d 2 [a, b] ⇠ 2 (min{f(c), f(d)},max{f(c), f(d)}) p 2 (c, d) f(p) = ⇠

f p 2 [a, b] f(p) = 0

(i) (ii) (iii) (iv)

(ii) (iii)

(i) (ii) (iv)

03. Questao: f : R ! R f(x) =

�a+ bx, x > 2

3, x = 2

b- ax

2

, x < 2

a, b 2 R

f a- b = 2

b- a = 2 f

a 2 (-1

2

, 0] b 2 [0, 1) f

f

a 2 (-1

2

, 0] b 2 [1, 2) f

04. Questao:x!0

x

4 + 5x- 1

2-px

2 + 4

x!1

x

3 - 1

(x- 1)2

+1+1

-1

Page 6: 2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04 ...conteudo.icmc.usp.br/pessoas/andcarva/sma301/Prova02_A_B_C_D.pdf · 2. PROVA DE SMA301-CALCULO I - Professor Alexandre

05. Questao: f(x) = |x+ 1|-px

2 + 2

f x = 1

2

y = 2

f [0, 1] y = 1 y = -1

f [0, 1] x = 1 x = -1

f y = 1 y = -1

f [0, 1]

06. Questao:x!0

⇣x

2 (3x)1- (x)

�x

2

�.

1

7

6

12

07. Questao: p(x) = 32x

5 - 80x

4 - 80x

3 + 200x

2 + 18x- 45

p(x)

p(x)

p(x)

p(x)

p(x)

08. Questao: f(x) =

✓2+ (

x

3 - 2

x

2 + 1

)

◆1+ (x2)

f

0(x) =�1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) =h ⇣

x

2-2

x

2+1

⌘ �1+ (x2)

�+ [1+ (x2)]

⇣2+

⇣x

3-2

x

2+1

⌘⌘i⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) =⇣2+

⇣x

3-2

x

2+1

⌘⌘1+ (x2)

1+ (x2)

2+⇣

x

3-2

x

2+1

⌘⇣

x

3-2

x

2+1

⌘x

4+3x

2+4x

(x2+1)2 - 2x (x2)⇣2+

⇣x

3-2

x

2+1

⌘⌘�

f

0(x) = 6x

(x2+1)2

⇣x

2-2

x

2+1

⌘ �1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) = -2x (x2)�1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

09. Questao: f : R \ {0} ! R f(x) = x

1

|x|f

f

f(0)

f

x!-1f(x) =

u!0

-

u

u

10. Questao:x!1

1

x

= 1

" > 0 � =

�1

2

,

"

2

� ����1

x

- 1

���� < " 0 < |x- 1| < �

" > 0 � = {1, 2"} 0 < |x- 1| < �

����1

x

- 1

���� < "

" > 0 � =

�1

2

,

"

2

�0 < |x- 1| < �

����1

x

- 1

���� < "

" > 0 � = {1, 2"}

����1

x

- 1

���� < " 0 < |x- 1| < �

x!1

1

x

= 1

x!1

+

1

x

= 1

x!1

-

1

x

= -1

Page 7: 2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04 ...conteudo.icmc.usp.br/pessoas/andcarva/sma301/Prova02_A_B_C_D.pdf · 2. PROVA DE SMA301-CALCULO I - Professor Alexandre

2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04.2013 - D

NOME: No. USP: NOTA:

Questao Resposta Valor Questao Resposta Valor

01a. (a) (b) (c) (d) (e) 06a. (a) (b) (c) (d) (e)

02a. (a) (b) (c) (d) (e) 07a. (a) (b) (c) (d) (e)

03a. (a) (b) (c) (d) (e) 08a. (a) (b) (c) (d) (e)

04a. (a) (b) (c) (d) (e) 09a. (a) (b) (c) (d) (e)

05a. (a) (b) (c) (d) (e) 10a. (a) (b) (c) (d) (e)

Regras: 1 - UNICA SEM RASURA2 -3 -

01. Questao:

f(x) =

�x+ 1, x ,

|x|+ 1, x .

g(x) =f(x)

|x|.

f Rf (-1, 0] g

f x = 0 g (0,1) g

f [0,1) g x = 0 g

f g R g

02. Questao: f : [a, b] ! R

f f

f M m (f) = [m,M]

c, d 2 [a, b] ⇠ 2 (min{f(c), f(d)},max{f(c), f(d)}) p 2 (c, d) f(p) = ⇠

f p 2 [a, b] f(p) = 0

(ii) (iii)

(i) (ii) (iii) (iv)

(i) (ii) (iv)

03. Questao:x!0

x

4 + 5x- 1

2-px

2 + 4

x!1

x

3 - 1

(x- 1)2

+1-1

+1

04. Questao: f(x) = |x+ 1|-px

2 + 2

f [0, 1] y = 1 y = -1

f x = 1

2

y = 2

f [0, 1] x = 1 x = -1

f [0, 1]

f y = 1 y = -1

Page 8: 2. PROVA DE SMA301-CALCULO I - Professor Alexandre 29.04 ...conteudo.icmc.usp.br/pessoas/andcarva/sma301/Prova02_A_B_C_D.pdf · 2. PROVA DE SMA301-CALCULO I - Professor Alexandre

05. Questao:x!0

⇣x

2 (3x)1- (x)

�x

2

�.

1

12

7

6

06. Questao: p(x) = 32x

5 - 80x

4 - 80x

3 + 200x

2 + 18x- 45

p(x)

p(x)

p(x)

p(x)

p(x)

07. Questao: f(x) =

✓2+ (

x

3 - 2

x

2 + 1

)

◆1+ (x2)

f

0(x) =�1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) =⇣2+

⇣x

3-2

x

2+1

⌘⌘1+ (x2)

1+ (x2)

2+⇣

x

3-2

x

2+1

⌘⇣

x

3-2

x

2+1

⌘x

4+3x

2+4x

(x2+1)2 - 2x (x2)⇣2+

⇣x

3-2

x

2+1

⌘⌘�

f

0(x) =h ⇣

x

2-2

x

2+1

⌘ �1+ (x2)

�+ [1+ (x2)]

⇣2+

⇣x

3-2

x

2+1

⌘⌘i⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) = 6x

(x2+1)2

⇣x

2-2

x

2+1

⌘ �1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

f

0(x) = -2x (x2)�1+ (x2)

� ⇣2+

⇣x

3-2

x

2+1

⌘⌘ (x2)

08. Questao: f : R ! R f(x) =

�a+ bx, x > 2

3, x = 2

b- ax

2

, x < 2

a, b 2 R

f a- b = 2

b- a = 2 f

a 2 (-1

2

, 0] b 2 [1, 2) f

f

a 2 (-1

2

, 0] b 2 [0, 1) f

09. Questao: f : R \ {0} ! R f(x) = x

1

|x|

x!-1f(x) =

u!0

-

u

u

f

f(0)

f

f

10. Questao:x!1

1

x

= 1

" > 0 � =

�1

2

,

"

2

�0 < |x- 1| < �

����1

x

- 1

���� < "

" > 0 � = {1, 2"} 0 < |x- 1| < �

����1

x

- 1

���� < "

" > 0 � =

�1

2

,

"

2

� ����1

x

- 1

���� < " 0 < |x- 1| < �

" > 0 � = {1, 2"}

����1

x

- 1

���� < " 0 < |x- 1| < �

x!1

1

x

= 1

x!1

+

1

x

= 1

x!1

-

1

x

= -1