unidades del almacenamiendo maria lozano
DESCRIPTION
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Jessica espejo parada
Ejercicios de conversin de unidades de almacenamiento1.RTA 4812,8 MB = 4,7 GB2. RTA :DVD _____________ 4,7 Gb 1 CD _______________ 700 Mb
1 Gb _______________ 1024 Mb
4,7 Gb ______________ X Mb
4,7 Gb . 1024 Mb_______________________ = 4.812,8 Mb
1 Gb
4812,8 Mb_________________ = 6,87 CDs
700 Mb
Respuesta: Necesitare 7 Cds3. RTA:700 MB * 2 CD= 1400 MB = 1,367 GBCualquier tarjeta que supere los 1400 MB o los 1,36 GB4RTA:1024 Kb ___________________ 1 Mb314528 Kb ___________________ X Mb
314528 Kb . 1Mb________________________ = 3072 Mb1024 Kb
1024 Mb _____________________ 1 Gb3072 Mb _____________________ X Gb
3072 Mb . 1 Gb_______________________ = 3 Gb1024 Mb
Respuesta: Elpendrive mas adecuado es en el de 4 Gb4. RTA:
Disco duro 2800 Mb
1024 Mb _________________ 1 Gb2800 Mb _________________ X Mb
2800 Mb . 1 Gb_____________________ = 2,73 Gb1024 Mb
Respuesta : Necesitara un DVD.5. RTA:100 temas 3072 Kb c/u = 307,200 Kb ( total )
1024 Kb _________________ 1 Mb307200 Kb _________________ X Mb
307200 Kb . 1 Mb__________________________ = 300 Mb1024 Kb
Respuesta: Si se podria bajar porque el mp3 tiene una capacidad de 512 Mb6. RTA:
Disco duro 2800 Mb
1024 Mb _________________ 1 Gb2800 Mb _________________ X Mb
2800 Mb . 1 Gb_____________________ = 2,73 Gb1024 Mb
Respuesta : Necesitara un DVD.
7. RTA: ESTA RESPUESTAS LAS MUESTRO DE DOS MANERAS DE LA SENCILLA1024/1024=1mb 2048/1024=2mb 5120/1024=5mb3072mb+2048mb+5mb+2mb+1mb=5128mb----->5gbY LA FORMA LARGA1024 Kb __________________ 1 Mb
1024 By _________________ 1 Kb2048 By _________________ X Kb
2048 By . 1 Kb________________________ = 2 Kb1024 By
1024 Kb __________________ 1 Mb
2 Kb __________________ X Mb
2 Kb. 1 Mb______________________ = 0,001 Mb
1024 Kb1024 Kb _______________________ 1 Mb
5012 Kb ________________________ X Mb
5012 Kb . 1 Mb__________________________ = 4,89 Mb
1024 Kb
Para guardar la informacion nesecitariamos una memoria usb de 5gb