I. Resultados: M e = 100g H 2 O M s = 50g H 2 OBalance de Masa dm dt= 50 ∫ 2000 m dm= ∫ 0 t50 dtm−2000 =50 t−0 dm dt= 50 Balance de Energía E e − E s = E ac E=mcpTE e − E s = dE dtm e c p Te − m s c p Te = d ( mcpT) dtm e c p Te − m s c p Te = cp [ dm dt.T+ dTdt. m ] 100 g . 4.18 Jg °C.20 ° C−50 g . 4.186 Jg ° CT= 4.186 [ 50 T+ dT[ 50 t+2000 ] dt] 8372−209.3 T=4.186x 50T+ 4.186 ( 50 T+2000 ) dTdt8372− 418.6 T=( 209.3 t+8372 ) dTdt1 209.3 [ ln| 209.3 t+ 8372 | −ln| 8372 | ] = 1 −418.6 [ ln| 8372−418.6 T| − ln| 8372− 418.6 ( 62) |] −2 ln| 209.3 t+8372| +18.06 =ln| 8372−418.6 T| −9.77 e −2l n| 209.3 t+8372| +27.83 = 8372−418.6