prueba
DESCRIPTION
Ejercicio sepTRANSCRIPT
DATOS:
G1 T1 Linea Load Motor Barra 3
Linea: Carga: Motor:
Carga Total:
Potencia que entrega el generador:
Perdidas en el sistema:
i 1 Sb 100 VbL1 100
Xg 0.1iXt 0.1i X 3 Sc 10 Sm
20
2 Vc 0.98 0 i
Sg 100Sbt 30 R 0.01 Vbc 110
Vg 6.6t1p 13.8 fp 0.8
Vbg VbL113.8
100 13.8
Xgn XgVg
Vbg
2
Sb
Sg 0.023i Xtg Xt
Vg
t1p
2
Sbt
Sg 6.862i 10
3
Xt1n Xtg13.8
Vbg
2
Sb
Sbt 0.023i
Zlr R i X 0.01 3iC1pu
Sc
Sb Cmpu
Sm fp( ) i Sm sin acos fp( )( )( )[ ]
Sb0.08 0.06i
Zb2VbL1
2
Sb100
ZlpuZlr
Zb21 10
4 0.03i Ctpu C1pu Cmpu 0.18 0.06i
V3pu VcVbc
VbL1
1.078
ICtpu
V3pu
V1pu V3pu I Zlpu Xt1n( ) 1.081 8.823i 103
Sg1 V1pu I 0.18 0.062i
Perdidas Sg1 Ctpu( ) Sb 3.098 104
0.164i
CARGA 1: Barra 5 G1: T1 LINEA 1: T2 LINEA 2:
ZL2 es igual 1/3*ZL1
CARGA 2:
Calcular Sg1 ???
SIN LA CARGA 2 Reactancias: G, T1, T2 Impedancias: L1, L2
CARGA 1 BARRA 5
CON LA CARGA 2
i 1
Sb 100 VbL1 200
C1 10 V5r 1 0iSg 10 St1 20 X 5 St2 20
Xg 0.1i N1 10 R 0.1 N3 200 Vb5 10 kV
Vg 10 N2 200 N4 10C2 10 i 20
Xt1 0.1i Xt2 0.1i
Vbg VbL1N1
N2 10 RL1pu 0.1
10
20010
200
2
100
20
0.5
Xgn Xg10
Vbg
2
Sb
Sg
iXL1pu 5 RL1pu 2.5
ZL1r RL1pu i XL1pu 0.5 2.5i
Xt1n Xt110
Vbg
2
Sb
St1
0.5i
ZbL1VbL1
2
Sb400
VbL2 VbL1N4
N3 10
ZL1puZL1r
ZbL11.25 10
3 6.25i 10
3
Xt2n Xt2N4
VbL2
2
Sb
St2 0.5i
ZL2r1
3
ZL1r 0.167 0.833i
ZbL2VbL2
2
Sb1
ZL2puZL2r
ZbL20.167 0.833i
Sc1r 10 0i MVAV5pu
V5r
Vb50.1
Sc1puSc1r
Sb0.1
IspuSc1pu
V5pu1
V1pu V5pu Ispu Xt1n ZL1pu Xt2n ZL2pu( ) 0.268 1.84i
Sg1 V1pu Ispu 0.268 1.84i
Sc2r 10 20 i
Sc2puSc2r
Sb
I2puSc2pu
V1pu
I1pu Ispu
Sg1_ V1pu I1pu I2pu( ) 0.229 2.06i