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PRCTICA 1. PROPIEDADES DE LOS FLUIDOS

SOLUCIN

DATOS:PLANETA TIERRA

m = 50 kgg = 3.5 m/s2 9.8 m/s2

2500kg/m3

CLCULOS:

a) = ! m=!

S": # = m$g

m = #/ g = %&0 kg

0.05'm3

() #= !

# = m$g = %32 N

%39.85288 kg*

=

Tam("+,: = m/

= m/ =

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SOLUCIN

DATOS:

- = & N.mN = 30m

! a1")L = 0.&5 mR = 0.%5 m

% = 2 = 0.003 m

CLCULOS:

0.&%2& m/s " =

L4 N67,)

= $ /% $ A ; $ /2 $ A

= /% ; /2) A

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- = /% ; /2) $ 2 $ " $ R%? 2 $ L

P7 @7 a,7:

= - / /% ; /2) $ 2 $ " $ R%? 2 $ LB

= 0.200% N.m/m3. s0.200% N.s/m2 Pa.s0.200%g/m.s

2.0 g/1m.s

- = /% ; /2) $ R% A

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3.%&%'

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SOLUCIN

DATOS:D = 0.005 mD1 = 0.00% m

0.52 N.m

S = %3.'% ga7 C@s"s = 5 mm

CLCULOS:

a) S" @a a , @ g 4 @ (7 ""7 s ,@aF ,7,1s , @ G"@"("7:

1$ 17s &5 = m$g

DsHa,7 @a a@a m1"7:

=

4 = 0

$ L $ 17s &5 = $ $g

$ L $ 17s &5 = $ A$

$ " $ D$ 17s &5 = $ "$ D?2/&)$

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0.0022m

0.0%%0m

La "*,1"a ,"@s g s:

D@a = 0.0088m

() a7 7 s"sm"17:

P7 @7 a,7F @ ",1m,7 maa s:

1.8 C.

= & $ 1s45 /

1= & $ 1s45 /

rror = Delta T =

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SOLUCIN

DATOS:

0.5 kg/1m2 DJ= 0F02K g=

CLCULOS:

s7,",7 =1

DJ=%;0.02/%002)) %

%.0002 % 0.0002

k= 2500.25kg/1m?2k= 0.250025kg/m?2

k= 2.&5 $%0?5 kPa

P=

2= %=2= %=

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9.8%N/g m2

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Ejemplo 1.1

a7s:M7m)= %33.3 ,/m?3

M= 0.2 m

s7@1"7,Pam)= M7m)$MPam)= %02.9 kPa/m?2

DATOS:%000 kg/m?3 g=

M= m%.0%39'(a

s7@1"7,

'8'0 gPa

Paga)=

Pam()=

P@)= M7aga)$g$MP@)=

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Ejemplo 1.3

DATOS:Sga1")= 0.9

D A)= 3m g= 9.8%D AC)= 'mD A)= %.5m

CLCULOS:

P,7 A:

PA)= 0 Pa ma,7m"1a)

P,7 :8.829kN/m3

A= 4M= 2'.&8kPa

P)= 2'.5kPama,7m"1a

P,7 C:

AC= 4$M= 53.0 kPa

4 a1"=

A ; A=

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PC)= 53.0 kPama,7m"17)

P,7 D:

PD)=P) 2'.5 kPama,7m"17)

P,7 E:

PE)=PA) 0 Pama,7m"17)

P,7 :

A= 4)$M= %3.2kPa

P)= %3.2 kPa

A ; AC=

A ; A=

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9.8%m/s?2

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kN/m3

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