meteorologia informe3
DESCRIPTION
TRANSMISORES, TEMPERATURATRANSCRIPT
![Page 1: METEOROLOGIA INFORME3](https://reader036.vdocumento.com/reader036/viewer/2022071709/563dbaa5550346aa9aa72535/html5/thumbnails/1.jpg)
3. Realizar las correcciones de la presión atmosférica a nivel de la estación (OVH) cuyas lecturas de los niveles de mercurio superior e inferior (ver tabla abajo) y usando la tabla I de manual de prácticas reducir la presión a nivel del mar.
Z1 (mm) 792 790 792 791 788 785 789 790 793Z2 (mm) 42 43 45 41 27 44 42 39 45THg (°C) 16.2 17.4 18.8 19.4 16.4 20.0 17.6 15.2 18.4Testación (°C) 21 23 22 21 24 20 26 22 21
a) ΔZ = 792 - 42 ΔZ = 750ΔZʼ = 750 - ϲΔZʼ = 750 - 3.58ΔZʼ = 746.42mm
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(746.42mm)P = 995.14 mb
P = Po.e[g.ΔZ/Rd.T]
P = (995.14).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*291K]
P = 1023.72 mb
b) ΔZ = 790 - 43ΔZ = 747ΔZʼ = 747 - ϲΔZʼ = 747 - 3.71ΔZʼ = 743.29mm
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(743.29mm)P = 990.97mb
P = Po.e[g.ΔZ/Rd.T]
P = (990.97).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*296K]
P = 1019.23 mb
Figura 1.La presión atmosférica disminuye con la altura porque el
espesor de las capas de aire es menor.
![Page 2: METEOROLOGIA INFORME3](https://reader036.vdocumento.com/reader036/viewer/2022071709/563dbaa5550346aa9aa72535/html5/thumbnails/2.jpg)
c) ΔZ = 792 - 45ΔZ = 747ΔZʼ = 747 - ϲΔZʼ = 747 - 3.88ΔZʼ = 743.12mm
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(743.12mm)P = 990.74 mb
P = Po.e[g.ΔZ/Rd.T]
P = (990.74).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*295K]
P = 1019.10 mb
d) ΔZ = 791 - 41ΔZ = 750ΔZʼ = 750 - ϲΔZʼ = 750 - 3.97ΔZʼ = 746.03mm
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(746.03mm)P = 994.6 mb
P = Po.e[g.ΔZ/Rd.T]
P = (994.6).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*294K]
P = 1023.17 mb
e) ΔZ = 788 - 37ΔZ = 751ΔZʼ = 751 - ϲΔZʼ = 751 - 3.60ΔZʼ = 747.40mm
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(747.40mm)P = 996.40 mb
Figura 2. Barómetro y experimento de Torricelli
Fig. 3 Todo el globo terestre está rodeado de una capa de aire
![Page 3: METEOROLOGIA INFORME3](https://reader036.vdocumento.com/reader036/viewer/2022071709/563dbaa5550346aa9aa72535/html5/thumbnails/3.jpg)
P = Po.e[g.ΔZ/Rd.T]
P = (996.40).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*297K]
P = 1025.02 mb
f) ΔZ = 785 - 44ΔZ = 741ΔZʼ = 741 - ϲΔZʼ = 741 - 4.01ΔZʼ = 736.99mm
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(736.99mm)P = 982.57 mb
P = Po.e[g.ΔZ/Rd.T]
P = (982.57).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*293K] P = 1010.90 mb
g) ΔZ = 789 - 42ΔZ = 747ΔZʼ = 747 - ϲΔZʼ = 747 - 3.72ΔZʼ = 743.28mm
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(743.28mm)P = 990.95 mb
P = Po.e[g.ΔZ/Rd.T] P = (990.95).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*296K]
P = 1019.22 mb
h) ΔZ = 790 - 39ΔZ = 751ΔZʼ = 751 - ϲΔZʼ = 751 - 3.46ΔZʼ = 747.54mm
Fig. 4 instrumentos de medida de la presión atmosférica.
![Page 4: METEOROLOGIA INFORME3](https://reader036.vdocumento.com/reader036/viewer/2022071709/563dbaa5550346aa9aa72535/html5/thumbnails/4.jpg)
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(747.54mm)P = 996.63mb
P = Po.e[g.ΔZ/Rd.T]
P = (996.63).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*295K]
P = 1023.16 mb
i) ΔZ = 793 - 45ΔZ = 748ΔZʼ = 748 - ϲ ΔZʼ = 748 - 3.85ΔZʼ = 744.15 mm
P = ρ.g.dzP = (13595 Kg/m3).(9.80667m/s2).(744.15 mm)P = 992.11mb
P = Po.e[g.ΔZ/Rd.T]
P = (992.11).e [9.80667m.s-2*247.7m/287.06JKg-1K-1*294K]
P = 1020.60 mb
Fig. 5. Los aneroides son unos aparatos metálicos utilizados para medir la presión atmosférica. Las variaciones de la presión atmosférica con el tiempo son registradas
por el aneroide en un papel.