mbr - ejercicio
DESCRIPTION
mbr, tabla, particionesTRANSCRIPT
EJERCICIO
1. Dado el código MBR siguiente, construya la tabla de particiones correspondiente.
Punto Inicial Punto Final
Sistema Boot Cabeza Cilindro Sector Cabeza Cilindro Sector
Sectores
Relativos No Sectores
EXT2FS NO 0 7 2 0 9 1 112456 32130
FAT32 NO 0 383 1 192 764 63 6152895 6132924
FAT16 SI 0 10 1 254 382 63 160650 5992245
EXTNDX NO 193 764 1 254 1023 63 12285819 46110456
00000000: FA 33 C0 8E D0 BC 00 7C - 8B F4 50 07 50 1F FB FC .3.....|..P.P.. 00000010: BF 00 06 B9 00 01 F2 A5 - EA 1D 06 00 00 50 55 8B .............PU. 00000020: EC C7 46 02 02 00 5D 50 - 55 8B EC C7 46 02 80 00 ..F...]PU...F... 00000030: 5D 50 55 8B EC C7 46 02 - 01 00 5D 50 55 8B EC C7 ]PU...F...]PU... 00000040: 46 02 02 00 5D 50 55 8B - EC C7 46 02 00 00 5D 50 F...]PU...F...]P 00000050: 55 8B EC C7 46 02 00 00 - 5D 50 55 8B EC C7 46 02 U...F...]PU...F. 00000060: 80 00 5D E8 7B 00 83 C4 - 0E E9 94 01 50 55 8B EC ..].{.......PU.. 00000070: C7 46 02 02 00 5D 50 55 - 8B EC C7 46 02 80 00 5D .F...]PU...F...] 00000080: 50 55 8B EC C7 46 02 01 - 00 5D 50 55 8B EC C7 46 PU...F...]PU...F 00000090: 02 03 00 5D 50 55 8B EC - C7 46 02 00 00 5D 50 55 ...]PU...F...]PU 000000A0: 8B EC C7 46 02 00 00 5D - 50 55 8B EC C7 46 02 C0 ...F...]PU...F.. 000000B0: 07 5D E8 2C 00 83 FF 00 - 75 22 B8 00 B8 8E C0 BE .].,....u"...... 000000C0: 00 00 26 C6 04 65 26 C6 - 44 02 72 26 C6 44 04 72 ..&..e&.D.r&.D.r 000000D0: 26 C6 44 06 6F 26 C6 44 - 08 72 EB FE EA 00 00 C0 &.D.o&.D.r...... 000000E0: 07 55 8B EC 83 EC 04 33 - C0 8B 46 04 8E C0 BB 00 .U.....3..F..... 000000F0: 00 80 7E 0E 80 72 0B C6 - 46 FD 3F C6 46 FC FF EB ..~..r..F.?.F... 00000100: 09 90 C6 46 FD 12 C6 46 - FC 01 8A 56 0E 8A 6E 06 ...F...F...V..n. 00000110: 8A 76 08 8A 4E 0A BF 0F - 00 8B 46 0C 51 B5 00 03 .v..N.....F.Q... 00000120: C1 8A 4E FD 3B C1 76 0B - 8A 46 FD FE C0 2A 46 0A ..N.;.v..F...*F. 00000130: EB 04 90 8B 46 0C 53 52 - 50 8C C1 81 E1 FF 0F BB ....F.SRP....... 00000140: 00 10 2B D9 BA 00 00 8B - C3 B9 20 00 F7 F1 8B D8 ..+....... ..... 00000150: 58 B4 00 3B C3 76 02 8B - C3 5A 5B 59 8A 66 10 57 X..;.v...Z[Y.f.W 00000160: 50 CD 13 58 5F 73 0A 33 - C0 CD 13 4F 75 AB EB 3D P..X_s.3...Ou..= 00000170: 90 B4 00 29 46 0C 00 46 - 0A 53 8C C3 83 C3 20 FE ...)F..F.S.... . 00000180: C8 75 F9 8E C3 5B 8A 46 - FD 38 46 0A 76 16 C6 46 .u...[.F.8F.v..F 00000190: 0A 01 FE 46 08 8A 46 FC - 38 46 08 76 07 C6 46 08 ...F..F.8F.v..F. 000001A0: 00 FE 46 06 83 7E 0C 00 - 74 03 E9 5D FF 8B 5E 04 ..F..~..t..]..^. 000001B0: 8A 46 0A 8A 6E 06 8A 4E - 08 8B E5 5D C3 00 00 00 .F..n..N...].... 000001C0: 02 07 83 00 01 09 48 B7 - 01 00 82 7D 00 00 00 00 ......H....}.... 000001D0: 41 7F 0B C0 BF FC BF E2 - 5D 00 BC 94 5D 00 80 00 A�......]...]... 000001E0: 01 0A 1E FE 7F 7E 8A 73 - 02 00 35 6F 5B 00 00 C1 ....�~.s..5o[... 000001F0: 81 FC 0F FE FF FF 7B 77 - BB 00 F8 96 BF 02 55 AA ......{w......U.