master presentation
TRANSCRIPT
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Submitted by:Jafar HasanpoorChair of Committee:
Stephen Morse Committee Member:
H.Scott Norville
Investigating the behavior of Glass Plate on Partial support
by Finite Elements Method using Abaqus/CAE
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Element Type:1500 mm X 1000 mm X 12 mm Load:0.5 kPa
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Define Boundary Condition
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Define Boundary Condition
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Assign partial support
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Define load
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Results
76 in. X 38 in. X 0.472in. AR=0.5, Load = 20.88psf
K=13.8 MPa (2000 psi) Rigid Simply Supported
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K=400 psi
K=2.6 MPa (400 psi) Partially Supported
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K=64 psi
K=0.45 MPa (64 psi) Partially Supported
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K=16 psi
K=0.11 MPa (16 psi) Partially Supported
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K=4 psi
K=0.027 MPa (4 psi) Partially Supported
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K=.01 psi (Free edge)
K = 0 MPa (0.01 psi) Free edge
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Maximum stress- stiffness chart AR=.5
Free edge
Simply supported
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Displacement - Stiffness chart AR=.5
Free edge
Simply supported
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Same Stiffness
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AR=2, 38in X 76 in
Thickness=.47 in Thickness=.74 in
Load=10.44psf
Load=20.88psf
Load=41.77psf
Stress=1475 psi Stress=584 psi
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AR=1
AR=2
Stress=986.7psi
Stress=584.2 psi