informe borrador campo electrico

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  • 8/18/2019 Informe borrador campo electrico

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    Datos Experiméntales:

    Cálculos:

    Determinación del radio promedio:

    r=√  x2+ y2

    r 35=√ (−1)2+(0)2=1

    r 35=√ (1)2+(0)2=1

    r 35=√ (0)2+(−1)2=1

    r 35=√ (1)2+(0)2=1

    r 35=√ (−0.8)2+(0.8)2=1.1

    r 35=√ (−0.8)2+(−0.8)2=1.1

    r 35=√ (0.8)2+(0.8)2=1.1

    r 35=√ (0.8)2+(−0.8)2=1.1

    r 35 prom=1+1+1+1+1.1+1.1+1.1+1.1

    8  =1.1cm

    TABLA I

    V1 = 35V V2 = 30V V3 = 25V V4 = 20V V5 = 15V V6 = 10VX1  Y1 X2  Y2 X3  Y3 X4  Y4 X5  Y5 X6  Y6

    -1 0 -1.6 0 -2.4 0 -3.6 0 -5.8 0 -9.4 0

    1 0 0 1.6 0 -2.4 3.6 0 0 5.8 0 -80 -1 1.6 0 2.4 0 0 3.6 5.8 0 9.4 0

    1 0 0 -1.6 0 2.4 0 -3.6 0 -5.8 0 8

    -0.8 0.8 -1.2 -1.2 -1.6 1.6 -2.6 -2.6 -4 -4 -6 6

    -0.8 -0.8 1.2 -1.2 1.6 1.6 2.6 -2.6 -4 4 -6 -6

    0.8 0.8 1.2 1.2 1.6 -1.6 2.6 2.6 4 4 6 -6

    0.8 -0.8 -1.2 1.2 -1.6 -1.6 -2.6 -2.6 4 -4 6 6

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    Determinación del Modelo Electrostático:

    A partir de la ecuación para el modelo potencial   y=b xm

    !   V =brm

    "allando el #alor de la pendiente

    m=ln (V 6)−ln (V 1)ln (r 6 )−ln (r 1)

    m=   ln  (10)−ln (35)ln (0.086 )−ln  (0.011)

    m=−0.61 volt 

    m

    "allando el #alor de $

    b=V 

    rm

    b=  30

    0.017−0.61

    b≈2.5

    %odelo &lectro't(tico V =2.5 . r−0.61 V 

    m

     )A*+A ,& VA+&/1 2 ! " #

    V#olt' 35 30 25 20 15 10rcm 1.1 1. 2.4 3. 5.8 8.6

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    Ma$nitudes del Campo Eléctrico:

     E=−∂V ∂r

     E=−V 2−V  1r 2−r 1

     E1=  −29−410.016−0.006

    =1200V  /m

     E2=  −25−34

    0.022−0.012=900V  /m

     E3=  −22−270.029−0.019

    =500V /m

     E4=  −17−21

    0.042−0.032=300V /m

     E5= −13.5−15.50.063−0.053

    =200V /m

     E6=   −10−9,5

    0.091−0.091=50V  /m

     )A*+A ,& VA+&/1 2 ! " #

    V#olt' 35 30 25 20 15 10rm 0.011 0.01 0.024 0.03 0.058 0.086

    &#olt'm

    1200 900 500 300 200 50