informe borrador campo electrico
TRANSCRIPT
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8/18/2019 Informe borrador campo electrico
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Datos Experiméntales:
Cálculos:
Determinación del radio promedio:
r=√ x2+ y2
r 35=√ (−1)2+(0)2=1
r 35=√ (1)2+(0)2=1
r 35=√ (0)2+(−1)2=1
r 35=√ (1)2+(0)2=1
r 35=√ (−0.8)2+(0.8)2=1.1
r 35=√ (−0.8)2+(−0.8)2=1.1
r 35=√ (0.8)2+(0.8)2=1.1
r 35=√ (0.8)2+(−0.8)2=1.1
r 35 prom=1+1+1+1+1.1+1.1+1.1+1.1
8 =1.1cm
TABLA I
V1 = 35V V2 = 30V V3 = 25V V4 = 20V V5 = 15V V6 = 10VX1 Y1 X2 Y2 X3 Y3 X4 Y4 X5 Y5 X6 Y6
-1 0 -1.6 0 -2.4 0 -3.6 0 -5.8 0 -9.4 0
1 0 0 1.6 0 -2.4 3.6 0 0 5.8 0 -80 -1 1.6 0 2.4 0 0 3.6 5.8 0 9.4 0
1 0 0 -1.6 0 2.4 0 -3.6 0 -5.8 0 8
-0.8 0.8 -1.2 -1.2 -1.6 1.6 -2.6 -2.6 -4 -4 -6 6
-0.8 -0.8 1.2 -1.2 1.6 1.6 2.6 -2.6 -4 4 -6 -6
0.8 0.8 1.2 1.2 1.6 -1.6 2.6 2.6 4 4 6 -6
0.8 -0.8 -1.2 1.2 -1.6 -1.6 -2.6 -2.6 4 -4 6 6
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Determinación del Modelo Electrostático:
A partir de la ecuación para el modelo potencial y=b xm
! V =brm
"allando el #alor de la pendiente
m=ln (V 6)−ln (V 1)ln (r 6 )−ln (r 1)
m= ln (10)−ln (35)ln (0.086 )−ln (0.011)
m=−0.61 volt
m
"allando el #alor de $
b=V
rm
b= 30
0.017−0.61
b≈2.5
%odelo &lectro't(tico V =2.5 . r−0.61 V
m
)A*+A ,& VA+&/1 2 ! " #
V#olt' 35 30 25 20 15 10rcm 1.1 1. 2.4 3. 5.8 8.6
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Ma$nitudes del Campo Eléctrico:
E=−∂V ∂r
E=−V 2−V 1r 2−r 1
E1= −29−410.016−0.006
=1200V /m
E2= −25−34
0.022−0.012=900V /m
E3= −22−270.029−0.019
=500V /m
E4= −17−21
0.042−0.032=300V /m
E5= −13.5−15.50.063−0.053
=200V /m
E6= −10−9,5
0.091−0.091=50V /m
)A*+A ,& VA+&/1 2 ! " #
V#olt' 35 30 25 20 15 10rm 0.011 0.01 0.024 0.03 0.058 0.086
&#olt'm
1200 900 500 300 200 50