ecuaciones literales
TRANSCRIPT
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7/26/2019 Ecuaciones Literales
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1.1.1.1.1. ( )a x + =1 1
2.2.2.2.2. ax bx = 4 2
3.3.3.3.3. ax b a bx+ = 2 2
4.4.4.4.4. ( )3 2 92a x ax a + = +
5.5.5.5.5. ( ) ( ) ( )a x b x b a b a x+ + = 2 2
6.6.6.6.6. ( ) ( ) ( )x a x a a a x + = 2 2
7
7.7.7.7.7. ( ) ( )ax a a b x ab + = +1
8.8.8.8.8. ( ) ( ) ( )a a x b x b b x b2 2 2 =
9.9.9.9.9. ( )( ) ( )( ) ( )x a x b x b x a b a a+ + = +2 2 3
10.10.10.10.10. ( ) ( )x a a x a a2 2
2
1+ = +
11.11.11.11.11. ( ) ( ) ( )m n x m n m mx a = 1
12.12.12.12.12. ( ) ( )x a ax a x a + = + 2 2 3 2 5
13.13.13.13.13. ( ) ( )a x a bx b b a x = 2 2
14.14.14.14.14. ( ) ( )( )ax bx x a b x b x a+ = + +2
2 2
15.15.15.15.15. ( ) ( ) ( ) ( )x a b a a x x a b+ = 3 2 2 1
16.16.16.16.16. ( )( ) ( ) ( )m x m x x m m x m+ + = + 4 3 2 152
17.17.17.17.17. ( ) ( ) ( ) ( ) ( )a a x a a b b x b b a a2 2 2 2
1 1 1 0 + + + =
18.18.18.18.18. ( ) ( )( ) ( ) ( ax b bx a a x x b a a b b = + + 2
2 2 21 2
19.19.19.19.19. ( ) ( ) ( )x b x a a b+ + =2 2 2
0
, pgina 244
SOLUCIONES pgina 559
EJERCICIO 143
Texto BALDOR
( ) ( )x m m x m x+ = +3 3 3 3
12 2
Curso: II 2016
Eje Temtico: ALGEBRA / ECUACIONES
Colegio de los Sagrados Corazones del Arzobispado de Santiago
20.
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7/26/2019 Ecuaciones Literales
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EJERCICIO 144
1.1.1.1.1.m
x m m = =1 2
2.2.2.2.2.a
x
b a
x+ =
2
4
3.3.3.3.3.x
a
x
a a2
1 1
22
=
4.4.4.4.4.m
x
n
m
n
x+ = +1
5.5.5.5.5.a
a
a
x
+ =
1 1
2
3 2
6.6.6.6.6.( )a x
a
b x
b
a b
ab
=
2
7.7.7.7.7.
x a
a
a x
ab a
= =
3 2 1
2
8.8.8.8.8.
x m
m
x n
n
m n
mn
+
+
=
+
=
2 2
2
9.9.9.9.9.x b
a
x a
b
=
2
10.10.10.10.10.4
2 3
3
2
x
a b+ = = +
11.11.11.11.11.( )2 3 2 64
a x
x a
x a
x a
+
+
=
+
12.12.12.12.12.( )
( )2
4
2
4
x c
x b
x c
x b
=
+
13.13.13.13.13.1 1 1
n
m
x mn x = =
14.14.14.14.14.( )( )
( )( )x b x a
x a a b x
+
+
=
2 2
22
15.15.15.15.15.x m
x n
n x
m x
+
=
+
+
16.16.16.16.16.( )( )x x b x b
x bx bx b m
2 3
32
2 2+ +
+
= + =
17.17.17.17.17.
3
4
1
3
5 13
12
x
b
x
a
x
b
x
a
a b
a+
=
+
+
18.18.18.18.18.( )x a x b
x a
ab b
x a
+=
+
3 33 3
9 3
22
19.19.19.19.19.
5
3
5
3
x a
x b
x b
x a
+
+=
20.20.20.20.20.( )x a
x a
x a
x a
a x ab
x a
+
+
=
+
2
2 2
21.21.21.21.21.2 3
42
11
162 2
x a
x a
a
x a
+
=
22.22.22.22.22.
1 2
2x a
x
a ax
x a
a++
+=
+
23.23.23.23.23.
( ) ( ) ( )2 3 6 22 2a xb
b x
a
a b
ab
+
+
=
, pgina 245
SOLUCIONES pgina 559Texto BALDOR