tanque imhoff
Post on 04-Jan-2016
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Tanque Imhoff
V=V s+V d+V n
V s=P×q× t
Donde:
P=746 [hab ]
q=0.70D
D=dotaciondeagua potableen l /hd
q=0.70×130=91[ lhd ]V s=746×91×2=135772 [ l ]
V d=P×Ld
Donde:
Ld=50 [l /hd ]
V d=746×50=37300 [l ]
V n=1.20 l
V=135772+37300+1.20
V=173073.2 [ l ]
Forma : rectangular
Dimensiones:
Ancho B = 6 m Largo L = 15 m Profundidad H = 7 m
Profundidad de cámara decantación h1=1.50 [m ] h2=1.70 [m ]
h3=2.60 [m ]
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