problema nª 2 hardy crossjgf

HEBER JORGE VALENZUELAPROBLEMA Nª2Determinar por metodo de Hardy Cross los caudales que circulan por cada uno de los ramales de la red de tuberias mostradas.

SOLUCION:

PRIMERA ITERACIONCIRCUITO I

tramo D (pulg) L(Km) Qo

1--2 12 1.2 100 -45

2--6 10 1.5 100 -30

6--5 10 1.2 120 25

1--5 16 1.5 100 70Σ

CIRCUITO II

tramo D (pulg) L(Km) Qo

1--3 14 2 100 55

3--4 10 1.5 100 30

4--5 10 2 120 -20

1--5 16 1.5 100 -70Σ

CIRCUITO III

tramo D (pulg) L(Km) Qo

6--5 10 1.2 120 -25

6--9 12 1.5 100 -35

9--8 8 1.2 100 -15

8--7 8 2 100 8

7--4 10 1.5 100 25

4--5 10 2 120 20Σ

SEGUNDA ITERACION

CIRCUITO Itramo D (pulg) L(Km) Qo

1--2 12 1.2 100 -38.999

2--6 10 1.5 100 -23.999

6--5 10 1.2 120 30.658

1--5 16 1.5 100 82.011Σ

CIRCUITO II

CH

CH

CH

CH

tramo D (pulg) L(Km) Qo

1--3 14 2 100 48.990

3--4 10 1.5 100 23.990

4--5 10 2 120 -26.352

1--5 16 1.5 100 -82.011Σ

CIRCUITO III

tramo D (pulg) L(Km) Qo

6--5 10 1.2 120 -30.658

6--9 12 1.5 100 -34.657

9--8 8 1.2 100 -14.657

8--7 8 2 100 8.343

7--4 10 1.5 100 25.343

4--5 10 2 120 26.352Σ

TERCERA ITERACION

CIRCUITO Itramo D (pulg) L(Km) Qo

1--2 12 1.2 100 -39.419

2--6 10 1.5 100 -24.419

6--5 10 1.2 120 30.503

1--5 16 1.5 100 80.897Σ

CIRCUITO II

tramo D (pulg) L(Km) Qo

1--3 14 2 100 49.684

3--4 10 1.5 100 24.684

4--5 10 2 120 -25.393

1--5 16 1.5 100 -80.897Σ

CIRCUITO III

tramo D (pulg) L(Km) Qo

6--5 10 1.2 120 -30.503

6--9 12 1.5 100 -34.923

9--8 8 1.2 100 -14.923

8--7 8 2 100 8.077

7--4 10 1.5 100 25.077

4--5 10 2 120 25.393Σ

CH

CH

CH

CH

CH

Q

Determinar por metodo de Hardy Cross los caudales que circulan por cada uno de los ramales de la red de tuberias mostradas.

h

hfh

m,

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.789 0.062 6.001 -38.999-3.987 0.133 6.001 -23.9991.624 0.065 5.658 30.6581.956 0.028 12.011 82.011-3.195 0.288

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ3.190 0.058 -6.010 48.9903.987 0.133 -6.010 23.990-1.792 0.090 -6.352 -26.352-1.956 0.028 -12.011 -82.0113.429 0.308

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-1.624 0.065 -5.658 -30.658-2.190 0.063 0.343 -34.657-2.611 0.174 0.343 -14.6571.360 0.170 0.343 8.3432.845 0.114 0.343 25.3431.792 0.090 6.352 26.352-0.428 0.675

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.140 0.055 -0.420 -39.419-2.638 0.110 -0.420 -24.4192.369 0.077 -0.155 30.5032.622 0.032 -1.114 80.8970.213 0.274

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ2.575 0.053 0.694 49.6842.636 0.110 0.694 24.684-2.985 0.113 0.959 -25.393-2.622 0.032 1.114 -80.897-0.395 0.308

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.369 0.077 0.155 -30.503-2.150 0.062 -0.266 -34.923-2.502 0.171 -0.266 -14.9231.470 0.176 -0.266 8.0772.918 0.115 -0.266 25.0772.985 0.113 -0.959 25.3930.351 0.715

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.183 0.055 0.007 -39.412-2.724 0.112 0.007 -24.4122.347 0.077 -0.055 30.4482.556 0.032 0.146 81.043-0.003 0.275

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ2.643 0.053 -0.139 49.5452.779 0.113 -0.139 24.545-2.787 0.110 -0.201 -25.595-2.556 0.032 -0.146 -81.0430.079 0.307

hfo(m) hfo/Qo ΔQ Q1 =Qo + ΔQ-2.347 0.077 0.055 -30.448-2.181 0.062 0.062 -34.861-2.586 0.173 0.062 -14.8611.385 0.171 0.062 8.1392.862 0.114 0.062 25.1392.787 0.110 0.201 25.595-0.081 0.708