algebra lineal primera practica dirigida

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EJEMPLO1 placa [A] [T] [C] [A] INVERSA 4 -1 -1 0 0 0 t1 150 0.29 0.1 0.1 0 -1 4 0 -1 0 0 t2 150 0.09 0.3 0 0.1 -1 0 4 -1 -1 0 t3 150 0.09 0 0.3 0.1 0 -1 -1 4 0 -1 t4 150 0.05 0.1 0.1 0.3 0 0 -1 0 4 -1 t5 150 0.03 0 0.1 0 0 0 0 -1 -1 4 t6 150 0.02 0 0 0.1 PARA HALLAR LA SOLUCION AL SISTEMA [A].[T]=[C] EJEMPLO2 0.866 0 -0.5 0 0 0 F1 0 0.87 0.5 0 0 0.5 0 0.866 0 0 0 F2 -1000 0.25 0 0 0 -0.866 -1 0 -1 0 0 F3 0 -0.5 0.9 0 0 -0.5 0 0 0 -1 0 H 0 -1 0 -1 0 0 1 0.5 0 0 0 V2 0 -0.4 0 0 -1 0 0 -0.866 0 0 1 V3 0 -0.4 0.7 0 0 EJEMPLO3 6 -4 0 X1 100 0.5 0.5 0.5 -4 6 -2 X2 200 0.5 0.8 0.8 0 -2 2 X3 100 0.5 0.7 1.3

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practica dirigida

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Hoja1EJEMPLO1placa [A][T][C][A] INVERSA4-1-1000t11500.29482401660.08612836440.09316770190.0496894410.02815734990.019461697785.7142857143=t1-140-100t21500.08612836440.29482401660.0496894410.09316770190.01946169770.028157349985.7142857143=t2-104-1-10t31500.09316770190.0496894410.32298136650.10559006210.09316770190.049689441107.1428571429=t30-1-140-1t41500.0496894410.09316770190.10559006210.32298136650.0496894410.0931677019107.1428571429=t400-104-1t51500.02815734990.01946169770.09316770190.0496894410.29482401660.086128364485.7142857143=t5000-1-14t61500.01946169770.02815734990.0496894410.09316770190.08612836440.294824016685.7142857143=t6PARA HALLAR LA SOLUCION AL SISTEMA[A].[T]=[C]EJEMPLO20.8660-0.5000F100.86603810570.5000220010000-500.022000968=F10.500.866000F2-10000.2500110005-0.43301905280010433.0190528383=F2-0.866-10-100F30-0.5000220010.86603810570000-866.0381056766=F3-0.5000-10H0-10-10-100=H010.5000V20-0.4330190528-0.25001100050-100250.011000484=V200-0.866001V30-0.43301905280.74998899950001-749.988999516=V3EJEMPLO36-40X11000.50.50.5200=X1-46-2X22000.50.750.75275=X20-22X31000.50.751.25325=X3